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Both upper block andlower block will have acceleration `2m/s^2` <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/HCV_VOL1_C06_E01_050_S01.png" width="80%"> <br> `R_1=mg F=mu R_1-T=0` <br> `rarr T-muR_1=0` <br> `and `F--mu mg =T` …..ii <br> `rarr T=mu mg` <br> Putting `T=mu mg` <br> `F=mu mg +mu mg = 2mu mg` <br> b. `2F=T-mumg -ma` <br> =0.........i <br> `T-ma-mu mg =0 [:.R=mg]` <br> `rarr T=ma+mumg` <br> Putting value of T in i. we have <br> `2F-Mamu mg +mu mg-ma=0` <br> Putting `F=2mumg` <br> 2(2mumg)-2mumg=a(M+m)` <br> `rarr4mu mg-2mumg=a(M+m)` <br> `rarr a=(2mu mg)/(M+m)` <br> Both blocks move with this acceleration a in opposite direction.