Re: I use exactly the same electrodes you show on...

>- anybody can try to measure the intensity circulating in the body with a multimeter and it will not be 9.6mA

Go figure! The multimeter has a resistance to it, often about 10 k-ohms. No wonder you are getting bad readings!

Place a 100 ohm resistor in series and measure the millivolts across it. Use the formula I=E/R, that is divide the volts by the resistance.

960 mv = 0.960 volts and divide by 100 yields 9.6 ma

>- I use salt water but please tell me what dosage you use and i will try to do it your way.

You are probably using a strong enough solution. 1 tsp in 6 to 8 oz of water. The problem is your method of measurement.

>- Mathematics with "assuming a body resistance of 730 ohms" is really not accurate and can't be proven, it is a theory. There are many parameters which can change the resistance of the human body. Your calculation can't be accurate.

That was provide as an example of one actual case. The others are also actual cases.

>- The other person "Retsel" i have mentionned before has made similar measures that i have done.

He was also using incorrect methods. Anytime that you insert a measuring device into a circuit, it influences the data.

>- With 45VDC (Five 9V batteries) :
45.0 Volts / 830 Ohms = 54.21 ma.

Thank God that you inserted the extra 10,000 ohms or you might bot have been here to keep us on our toes :^) According to Underwriters Lab, any voltage greater than 24 volts is potentially deadly. This is why most vehicles, boats, etc. use either 12 volts or 24 volts but not higher.

Retry the measurements at a safe voltage and using a 1 percent 100 ohm resistor. I think that you will find a major difference.

The reading found will be the average ma and you want the peak ma.

To get the real voltage and milliamps, divide the reading by the duty cycle.

4.8 ma / 0.5 ( 50 percent ) = 9.6 ma peak

8.6 ma / .9 ( 90 percent duty cycle ) = 9.6 ma peak

I hope that this resolves at least some of your issues and please let us know what you find.